Rolle's Theorem
If is continuous on and differentiable on with , then with .
Proposition 3.10 (Rolle's Theorem)
Let be continuous on and differentiable on . If , then such that .
Proof
By the Extreme Value Theorem, attains its maximum and its minimum on : there are with
If an extremum lies in the open interval, say , then has the same sign as ; taking the limits along and forces . Similarly for a maximum , where the difference quotient has sign opposite to .
If is not constant, then either or , so at least one of , cannot sit at the endpoints and must lie in . If is constant the result is trivial.
Related
Stated in
- Proposition 3.10 (Rolle's Theorem)ยง3.2 Mean Value Theorems
