Stirling's Formula
as , where means .
Theorem 1.5 (Stirling's Formula)
As , we have
Logarithmic form
as .
Writing and comparing with and , integration from to gives
and dividing by shows that .
Proof
For twice differentiable and , integration by parts twice gives
Taking , , and summing over ,
where
So the series converges, and
for the constant .
It remains to show that . The Wallis integrals
satisfy by integration by parts, so
Since and is decreasing in , sandwiching gives , hence
On the other hand, Stirling’s asymptotic form with the constant gives . Comparing the two forces .
Related
Stated in
- Theorem 1.5 (Stirling's Formula)§1.3 Stirling’s Formula
